What is log_{8}(3)+log_{8}(x^3-2)+log_{8}(2) ?

The solution to log_{8}(3)+log_{8}(x^3-2)+log_{8}(2) is log_{8}(6(x^3-2))

Popular >

simplify log_{8}(3)+log_{8}(x^3-2)+log_{8}(2)

simplify

lo g_{8} (3) + lo g_{8} (x^{3} - 2) + lo g_{8} (2)

lo g_{8} (6 (x^{3} - 2))

Solution steps

lo g_{8} (3) + lo g_{8} (x^{3} - 2) + lo g_{8} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{8} (3) + lo g_{8} (x^{3} - 2) = lo g_{8} (3 (x^{3} - 2))

= lo g_{8} (3 (x^{3} - 2)) + lo g_{8} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{8} (3 (x^{3} - 2)) + lo g_{8} (2) = lo g_{8} (3 (x^{3} - 2) \cdot 2)

= lo g_{8} (3 (x^{3} - 2) \cdot 2)

Multiply the numbers:

3 \cdot 2 = 6

= lo g_{8} (6 (x^{3} - 2))

lo g_{10} (\frac{4 ( x + 6 ) ^{5}}{x ^{3}})

ln (\frac{1}{9 ^{k}})

ln (\frac{x + 1}{x - 1})

ln (2 x) + 3 (ln (x) - ln (y))

\frac{1}{2} ln (x + 3) + \frac{1}{2} ln (x + 2)

What is log_{8}(3)+log_{8}(x^3-2)+log_{8}(2) ?
The solution to log_{8}(3)+log_{8}(x^3-2)+log_{8}(2) is log_{8}(6(x^3-2))