What are the solutions to the equation m^2-3m+2=0 ?

The solutions to the equation m^2-3m+2=0 are m=2,m=1

Find the zeros of m^2-3m+2=0

The zeros of m^2-3m+2=0 are m=2,m=1

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m^{2} - 3 m + 2 = 0

m = 2, m = 1

Solution steps

m^{2} - 3 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

m_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

m = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

m = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

m = 2, m = 1

x^{2} + 14 x - 5 = 0

x, x^{2} + y^{2} + z^{2} = 1

x^{2} - 10 x

x, y^{2} = x^{2}

4 x^{2} - 20 x = - 21

What are the solutions to the equation m^2-3m+2=0 ?
The solutions to the equation m^2-3m+2=0 are m=2,m=1
Find the zeros of m^2-3m+2=0
The zeros of m^2-3m+2=0 are m=2,m=1