What are the solutions to the equation solvefor x,x^2+2xy-4+y^2=0 ?

The solutions to the equation solvefor x,x^2+2xy-4+y^2=0 are x=-y+2,x=-y-2

Find the zeros of solvefor x,x^2+2xy-4+y^2=0

The zeros of solvefor x,x^2+2xy-4+y^2=0 are x=-y+2,x=-y-2

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solve for

x, x^{2} + 2 x y - 4 + y^{2} = 0

x = - y + 2, x = - y - 2

Solution steps

x^{2} + 2 x y - 4 + y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 y x - 4 + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 y \pm ( 2 y ) ^{2} - 4 \cdot 1 \cdot ( - 4 + y ^{2} )}{2 \cdot 1}

(2 y)^{2} - 4 \cdot 1 \cdot (- 4 + y^{2}) = 4

x_{1, 2} = \frac{- 2 y \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 y + 4}{2 \cdot 1}, x_{2} = \frac{- 2 y - 4}{2 \cdot 1}

x = \frac{- 2 y + 4}{2 \cdot 1} : - y + 2

x = \frac{- 2 y - 4}{2 \cdot 1} : - y - 2

The solutions to the quadratic equation are:

x = - y + 2, x = - y - 2

(x + 4)^{2} = 63

x, - 5 x^{2} + 60 x + 7 y^{2} + 84 y + 72 = 0

3 x^{2} - 5 x + 8 = 0

(2 x - 3)^{2} = 169

x^{2} - 12 x + 100 = 0

What are the solutions to the equation solvefor x,x^2+2xy-4+y^2=0 ?
The solutions to the equation solvefor x,x^2+2xy-4+y^2=0 are x=-y+2,x=-y-2
Find the zeros of solvefor x,x^2+2xy-4+y^2=0
The zeros of solvefor x,x^2+2xy-4+y^2=0 are x=-y+2,x=-y-2