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受欢迎的代数 >

(1-k)x^2-(k+1)x-2=0

解答

(1 - k) x^{2} - (k + 1) x - 2 = 0

解答

x = - 1, x = \frac{2}{1 - k}; k \neq = 1

求解步骤

(1 - k) x^{2} - (k + 1) x - 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - k - 1 ) \pm ( - k - 1 ) ^{2} - 4 ( 1 - k ) ( - 2 )}{2 ( 1 - k )}

化简

(- k - 1)^{2} - 4 (1 - k) (- 2) : k - 3

x_{1, 2} = \frac{- ( - k - 1 ) \pm ( k - 3 )}{2 ( 1 - k )}; k \neq = 1

将解分隔开

x_{1} = \frac{- ( - k - 1 ) + k - 3}{2 ( 1 - k )}, x_{2} = \frac{- ( - k - 1 ) - ( k - 3 )}{2 ( 1 - k )}

x = \frac{- ( - k - 1 ) + k - 3}{2 ( 1 - k )} : - 1

x = \frac{- ( - k - 1 ) - ( k - 3 )}{2 ( 1 - k )} : \frac{2}{1 - k}

二次方程组的解是:

x = - 1, x = \frac{2}{1 - k}; k \neq = 1

作图

流行的例子

(x + 2) (x - 3) = 6

solvefor x,x^2y+xy^2=6

so l v e f or x, x^{2} y + x y^{2} = 6

4 x^{2} + 2 = 38

12 x + 36 = - x^{2}

2 (x^{2} - 6) + 8 = 10