What are the solutions to the equation 4x^2-36x=-85 ?

The solutions to the equation 4x^2-36x=-85 are x= 9/2+i,x= 9/2-i

Find the zeros of 4x^2-36x=-85

The zeros of 4x^2-36x=-85 are x= 9/2+i,x= 9/2-i

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4 x^{2} - 36 x = - 85

x = \frac{9}{2} + i, x = \frac{9}{2} - i

Solution steps

4 x^{2} - 36 x = - 85

Move

85

to the left side

4 x^{2} - 36 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 85}{2 \cdot 4}

Simplify

(- 36)^{2} - 4 \cdot 4 \cdot 85 : 8 i

x_{1, 2} = \frac{- ( - 36 ) \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8 i}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 8 i}{2 \cdot 4}

x = \frac{- ( - 36 ) + 8 i}{2 \cdot 4} : \frac{9}{2} + i

x = \frac{- ( - 36 ) - 8 i}{2 \cdot 4} : \frac{9}{2} - i

The solutions to the quadratic equation are:

x = \frac{9}{2} + i, x = \frac{9}{2} - i

5 x^{2} + 2 x - 1 = 0

4 x^{2} + 9 = - 4 x

- 6 x^{2} + 103 x - 17 = 0

n^{2} - 6 = - n

2 x^{2} + 11 = 131

What are the solutions to the equation 4x^2-36x=-85 ?
The solutions to the equation 4x^2-36x=-85 are x= 9/2+i,x= 9/2-i
Find the zeros of 4x^2-36x=-85
The zeros of 4x^2-36x=-85 are x= 9/2+i,x= 9/2-i