What are the solutions to the equation w^2-1/15 w= 2/15 ?

The solutions to the equation w^2-1/15 w= 2/15 are w= 2/5 ,w=-1/3

Find the zeros of w^2-1/15 w= 2/15

The zeros of w^2-1/15 w= 2/15 are w= 2/5 ,w=-1/3

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w^{2} - \frac{1}{15} w = \frac{2}{15}

w = \frac{2}{5}, w = - \frac{1}{3}

Decimal Notation

w = 0.4, w = - 0.33333 \dots

Solution steps

w^{2} - \frac{1}{15} w = \frac{2}{15}

Multiply both sides by

15

15 w^{2} - w = 2

Move

2

to the left side

15 w^{2} - w - 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 15 ( - 2 )}{2 \cdot 15}

(- 1)^{2} - 4 \cdot 15 (- 2) = 11

w_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 15}

Separate the solutions

w_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 15}, w_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 15}

w = \frac{- ( - 1 ) + 11}{2 \cdot 15} : \frac{2}{5}

w = \frac{- ( - 1 ) - 11}{2 \cdot 15} : - \frac{1}{3}

The solutions to the quadratic equation are:

w = \frac{2}{5}, w = - \frac{1}{3}

x^{2} + 5 x

x, y^{3} = x^{2}

(2 x + 4)^{2} = 100

x^{2} + 8 x + 16 = 64

5 (x - 7)^{2} + 27 = 32

What are the solutions to the equation w^2-1/15 w= 2/15 ?
The solutions to the equation w^2-1/15 w= 2/15 are w= 2/5 ,w=-1/3
Find the zeros of w^2-1/15 w= 2/15
The zeros of w^2-1/15 w= 2/15 are w= 2/5 ,w=-1/3