12x^2-156x+350=0

Lösung

12 x^{2} - 156 x + 350 = 0

x = \frac{39 + 471}{6}, x = \frac{39 - 471}{6}

Dezimale

x = 10.11708 \dots, x = 2.88291 \dots

Schritte zur Lösung

12 x^{2} - 156 x + 350 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- ( - 156 ) \pm ( - 156 ) ^{2} - 4 \cdot 12 \cdot 350}{2 \cdot 12}

(- 156)^{2} - 4 \cdot 12 \cdot 350 = 4471

x_{1, 2} = \frac{- ( - 156 ) \pm 4 471}{2 \cdot 12}

Trenne die Lösungen

x_{1} = \frac{- ( - 156 ) + 4 471}{2 \cdot 12}, x_{2} = \frac{- ( - 156 ) - 4 471}{2 \cdot 12}

x = \frac{- ( - 156 ) + 4 471}{2 \cdot 12} : \frac{39 + 471}{6}

x = \frac{- ( - 156 ) - 4 471}{2 \cdot 12} : \frac{39 - 471}{6}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{39 + 471}{6}, x = \frac{39 - 471}{6}

x^{2} + 5 x = 2.75

f a c t or x^{2} - x = 0

8 x^{2} + 5 x - 6 = 0

3 x^{2} - 22 x + 24 = 0

(x + 5)^{2} - 6 = 43