(x-7)^3(x+2)^2(x-13)<0

Lösung

(x - 7)^{3} (x + 2)^{2} (x - 13) < 0

7 < x < 13

Intervall-Notation

(7, 13)

Schritte zur Lösung

(x - 7)^{3} (x + 2)^{2} (x - 13) < 0

Identifiziere die Intervalle

7 < x < 13

2 x^{2} + 8 x - 7 = 0

4 x = x^{2} - 12

4 x^{2} + x - 7 = 0

x = \frac{9 ( - 3 ) - 2 ( - 2 )}{15 ( - 3 ) - 3 ( - 2 )}

8 - \frac{x}{3} \leq 7