What are the solutions to the equation solvefor x,3x^2+3y^2+3z^2=27 ?

The solutions to the equation solvefor x,3x^2+3y^2+3z^2=27 are x=sqrt(9-y^2-z^2),x=-sqrt(9-y^2-z^2)

Find the zeros of solvefor x,3x^2+3y^2+3z^2=27

The zeros of solvefor x,3x^2+3y^2+3z^2=27 are x=sqrt(9-y^2-z^2),x=-sqrt(9-y^2-z^2)

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solve for

x, 3 x^{2} + 3 y^{2} + 3 z^{2} = 27

x = 9 - y^{2} - z^{2}, x = - 9 - y^{2} - z^{2}

Solution steps

3 x^{2} + 3 y^{2} + 3 z^{2} = 27

Move

3 y^{2}

to the right side

3 x^{2} + 3 z^{2} = 27 - 3 y^{2}

Move

3 z^{2}

to the right side

3 x^{2} = 27 - 3 y^{2} - 3 z^{2}

Divide both sides by

3

x^{2} = 9 - y^{2} - z^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9 - y^{2} - z^{2}, x = - 9 - y^{2} - z^{2}

ab x^{2} + ab = x (a^{2} + b^{2})

x^{2} = \frac{7}{5}

s^{2} - 6 s + 10

x, - 3 x^{2} + 2 x y + y^{2} = 0

(x + 2)^{2} - 3 = x - 2

What are the solutions to the equation solvefor x,3x^2+3y^2+3z^2=27 ?
The solutions to the equation solvefor x,3x^2+3y^2+3z^2=27 are x=sqrt(9-y^2-z^2),x=-sqrt(9-y^2-z^2)
Find the zeros of solvefor x,3x^2+3y^2+3z^2=27
The zeros of solvefor x,3x^2+3y^2+3z^2=27 are x=sqrt(9-y^2-z^2),x=-sqrt(9-y^2-z^2)