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人気のある代数 >

(1+x)^2+(2+x)^2=(3-x)^2

解

(1 + x)^{2} + (2 + x)^{2} = (3 - x)^{2}

解

x = 2 (10 - 3), x = - 2 (3 + 10)

+1

十進法表記

x = 0.32455 \dots, x = - 12.32455 \dots

解答ステップ

(1 + x)^{2} + (2 + x)^{2} = (3 - x)^{2}

拡張

(1 + x)^{2} + (2 + x)^{2} : 2 x^{2} + 6 x + 5

拡張

(3 - x)^{2} : 9 - 6 x + x^{2}

2 x^{2} + 6 x + 5 = 9 - 6 x + x^{2}

x^{2}

を左側に移動します

x^{2} + 6 x + 5 = 9 - 6 x

6 x

を左側に移動します

x^{2} + 12 x + 5 = 9

9

を左側に移動します

x^{2} + 12 x - 4 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 4) = 410

x_{1, 2} = \frac{- 12 \pm 4 10}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 12 + 4 10}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 10}{2 \cdot 1}

x = \frac{- 12 + 4 10}{2 \cdot 1} : 2 (10 - 3)

x = \frac{- 12 - 4 10}{2 \cdot 1} : - 2 (3 + 10)

二次equationの解:

x = 2 (10 - 3), x = - 2 (3 + 10)

グラフ

人気の例

solvefor v,a=(v^2)/r

so l v e f or v, a = \frac{v ^{2}}{r}

x^{2} - 4 x = 13

solvefor x,4x^2-y^2=0

so l v e f or x, 4 x^{2} - y^{2} = 0

(x^2)/4-(x^2)/5 =1

\frac{x ^{2}}{4} - \frac{x ^{2}}{5} = 1

2(11-x^2)=(5-x)^2

2 (11 - x^{2}) = (5 - x)^{2}