What are the solutions to the equation 4x^2-4x+11=0 ?

The solutions to the equation 4x^2-4x+11=0 are x= 1/2+isqrt(5/2),x= 1/2-isqrt(5/2)

Find the zeros of 4x^2-4x+11=0

The zeros of 4x^2-4x+11=0 are x= 1/2+isqrt(5/2),x= 1/2-isqrt(5/2)

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4 x^{2} - 4 x + 11 = 0

x = \frac{1}{2} + i \frac{5}{2}, x = \frac{1}{2} - i \frac{5}{2}

Solution steps

4 x^{2} - 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 11}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 11 : 410 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 10 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 10 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 4 10 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 4 10 i}{2 \cdot 4} : \frac{1}{2} + i \frac{5}{2}

x = \frac{- ( - 4 ) - 4 10 i}{2 \cdot 4} : \frac{1}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{5}{2}, x = \frac{1}{2} - i \frac{5}{2}

y, z = x^{3} + 3 x y^{2} - 15 x - 12 y

9 y^{2} = 4

8 x^{2} - 8 x - 6 = 0

x^{2} + 5 = 5 x

a^{2} = 12

What are the solutions to the equation 4x^2-4x+11=0 ?
The solutions to the equation 4x^2-4x+11=0 are x= 1/2+isqrt(5/2),x= 1/2-isqrt(5/2)
Find the zeros of 4x^2-4x+11=0
The zeros of 4x^2-4x+11=0 are x= 1/2+isqrt(5/2),x= 1/2-isqrt(5/2)