What are the solutions to the equation n^2-5n-6=0 ?

The solutions to the equation n^2-5n-6=0 are n=6,n=-1

Find the zeros of n^2-5n-6=0

The zeros of n^2-5n-6=0 are n=6,n=-1

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n^{2} - 5 n - 6 = 0

n = 6, n = - 1

Solution steps

n^{2} - 5 n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

n_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, n_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

n = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

n = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 6, n = - 1

1.25 x^{2} - 25 x + 5 = 0

4 x^{2} - x + 1 = x + 3 x^{2}

y^{2} = - 5

x, x^{2} = 9

36 x^{2} + 4 = 0

What are the solutions to the equation n^2-5n-6=0 ?
The solutions to the equation n^2-5n-6=0 are n=6,n=-1
Find the zeros of n^2-5n-6=0
The zeros of n^2-5n-6=0 are n=6,n=-1