What are the solutions to the equation y^2-13y-30=0 ?

The solutions to the equation y^2-13y-30=0 are y=15,y=-2

Find the zeros of y^2-13y-30=0

The zeros of y^2-13y-30=0 are y=15,y=-2

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y^{2} - 13 y - 30 = 0

y = 15, y = - 2

Solution steps

y^{2} - 13 y - 30 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 30) = 17

y_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 1}, y_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 1}

y = \frac{- ( - 13 ) + 17}{2 \cdot 1} : 15

y = \frac{- ( - 13 ) - 17}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 15, y = - 2

2 e^{2} + 8 = e

11 x^{2} + 1 = 2 x^{2}

2 y^{2} - 6 y + 3 = 0

6 x^{2} - 29 x + 20 = 0

(m^{2} + 4) = 0

What are the solutions to the equation y^2-13y-30=0 ?
The solutions to the equation y^2-13y-30=0 are y=15,y=-2
Find the zeros of y^2-13y-30=0
The zeros of y^2-13y-30=0 are y=15,y=-2