What are the solutions to the equation 2x^2+12x+35/2 =0 ?

The solutions to the equation 2x^2+12x+35/2 =0 are x=-5/2 ,x=-7/2

Find the zeros of 2x^2+12x+35/2 =0

The zeros of 2x^2+12x+35/2 =0 are x=-5/2 ,x=-7/2

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2 x^{2} + 12 x + \frac{35}{2} = 0

x = - \frac{5}{2}, x = - \frac{7}{2}

Decimal Notation

x = - 2.5, x = - 3.5

Solution steps

2 x^{2} + 12 x + \frac{35}{2} = 0

Multiply both sides by

2

4 x^{2} + 24 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 35}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 35 = 4

x_{1, 2} = \frac{- 24 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 4}{2 \cdot 4}, x_{2} = \frac{- 24 - 4}{2 \cdot 4}

x = \frac{- 24 + 4}{2 \cdot 4} : - \frac{5}{2}

x = \frac{- 24 - 4}{2 \cdot 4} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = - \frac{7}{2}

5 x^{2} + 7 x + 1 = 0

2 x^{2} + 18 x + 39 = 0

x^{2} + 2 x + 25 = 0

x, x^{2} - 2 x y + y^{2} - 1 = 0

x^{2} + 21 x = 11 - x^{2}

What are the solutions to the equation 2x^2+12x+35/2 =0 ?
The solutions to the equation 2x^2+12x+35/2 =0 are x=-5/2 ,x=-7/2
Find the zeros of 2x^2+12x+35/2 =0
The zeros of 2x^2+12x+35/2 =0 are x=-5/2 ,x=-7/2