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受欢迎的代数 >

12a^3-15x^2+16x-20=0

解答

12 a^{3} - 15 x^{2} + 16 x - 20 = 0

解答

x = - \frac{2 ( 45 a ^{3} - 59 - 4 )}{15}, x = \frac{2 ( 45 a ^{3} - 59 + 4 )}{15}

求解步骤

12 a^{3} - 15 x^{2} + 16 x - 20 = 0

改写成标准形式

a x^{2} + b x + c = 0

- 15 x^{2} + 16 x + 12 a^{3} - 20 = 0

使用求根公式求解

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 15 ) ( 12 a ^{3} - 20 )}{2 ( - 15 )}

化简

1 6^{2} - 4 (- 15) (12 a^{3} - 20) : 4 45 a^{3} - 59

x_{1, 2} = \frac{- 16 \pm 4 45 a ^{3} - 59}{2 ( - 15 )}

将解分隔开

x_{1} = \frac{- 16 + 4 45 a ^{3} - 59}{2 ( - 15 )}, x_{2} = \frac{- 16 - 4 45 a ^{3} - 59}{2 ( - 15 )}

x = \frac{- 16 + 4 45 a ^{3} - 59}{2 ( - 15 )} : - \frac{2 ( 45 a ^{3} - 59 - 4 )}{15}

x = \frac{- 16 - 4 45 a ^{3} - 59}{2 ( - 15 )} : \frac{2 ( 45 a ^{3} - 59 + 4 )}{15}

二次方程组的解是:

x = - \frac{2 ( 45 a ^{3} - 59 - 4 )}{15}, x = \frac{2 ( 45 a ^{3} - 59 + 4 )}{15}

作图

流行的例子

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