What are the solutions to the equation x^2-13x=x-49 ?

The solutions to the equation x^2-13x=x-49 are x=7

Find the zeros of x^2-13x=x-49

The zeros of x^2-13x=x-49 are x=7

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x^{2} - 13 x = x - 49

x = 7

Solution steps

x^{2} - 13 x = x - 49

Move

49

to the left side

x^{2} - 13 x + 49 = x

Move

x

to the left side

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

x^{2} - 2 x + 100 = 0

4 n^{2} - 36 = 0

b^{2} + 4 b = 8

2 x - 2 x^{2} = 0

(y + 3) + y^{2} = 1

What are the solutions to the equation x^2-13x=x-49 ?
The solutions to the equation x^2-13x=x-49 are x=7
Find the zeros of x^2-13x=x-49
The zeros of x^2-13x=x-49 are x=7