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受欢迎的代数 >

39y^2-148y+132=0

解答

39 y^{2} - 148 y + 132 = 0

解答

y = \frac{2 ( 37 + 82 )}{39}, y = \frac{2 ( 37 - 82 )}{39}

+1

十进制

y = 2.36181 \dots, y = 1.43305 \dots

求解步骤

39 y^{2} - 148 y + 132 = 0

使用求根公式求解

y_{1, 2} = \frac{- ( - 148 ) \pm ( - 148 ) ^{2} - 4 \cdot 39 \cdot 132}{2 \cdot 39}

(- 148)^{2} - 4 \cdot 39 \cdot 132 = 482

y_{1, 2} = \frac{- ( - 148 ) \pm 4 82}{2 \cdot 39}

将解分隔开

y_{1} = \frac{- ( - 148 ) + 4 82}{2 \cdot 39}, y_{2} = \frac{- ( - 148 ) - 4 82}{2 \cdot 39}

y = \frac{- ( - 148 ) + 4 82}{2 \cdot 39} : \frac{2 ( 37 + 82 )}{39}

y = \frac{- ( - 148 ) - 4 82}{2 \cdot 39} : \frac{2 ( 37 - 82 )}{39}

二次方程组的解是:

y = \frac{2 ( 37 + 82 )}{39}, y = \frac{2 ( 37 - 82 )}{39}

作图

流行的例子

(4x+1)^2+9(4x+1)=-18

(4 x + 1)^{2} + 9 (4 x + 1) = - 18

solvefor x,5x^2-12y^2+3xy^2=10

so l v e f or x, 5 x^{2} - 12 y^{2} + 3 x y^{2} = 10

x^{2} = - 15

(3 p + 2)^{2} = 8

p^{2} + 8 p = 0