What are the solutions to the equation solvefor p,3p^2+12p=6 ?

The solutions to the equation solvefor p,3p^2+12p=6 are p=-2+sqrt(6),p=-2-sqrt(6)

Find the zeros of solvefor p,3p^2+12p=6

The zeros of solvefor p,3p^2+12p=6 are p=-2+sqrt(6),p=-2-sqrt(6)

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p, 3 p^{2} + 12 p = 6

p = - 2 + 6, p = - 2 - 6

Decimal Notation

p = 0.44948 \dots, p = - 4.44948 \dots

Solution steps

3 p^{2} + 12 p = 6

Move

6

to the left side

3 p^{2} + 12 p - 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 6) = 66

p_{1, 2} = \frac{- 12 \pm 6 6}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- 12 + 6 6}{2 \cdot 3}, p_{2} = \frac{- 12 - 6 6}{2 \cdot 3}

p = \frac{- 12 + 6 6}{2 \cdot 3} : - 2 + 6

p = \frac{- 12 - 6 6}{2 \cdot 3} : - 2 - 6

The solutions to the quadratic equation are:

p = - 2 + 6, p = - 2 - 6

s^{2} + s + 12 = 0

x^{2} - 1 x - 2 = 0

n^{2} - 4 n + 4 = 0

49 = x^{2}

6 x^{2} = 36 x

What are the solutions to the equation solvefor p,3p^2+12p=6 ?
The solutions to the equation solvefor p,3p^2+12p=6 are p=-2+sqrt(6),p=-2-sqrt(6)
Find the zeros of solvefor p,3p^2+12p=6
The zeros of solvefor p,3p^2+12p=6 are p=-2+sqrt(6),p=-2-sqrt(6)