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受欢迎的代数 >

solvefor x,f=2x^2-x+2k

解答

求解

x, f = 2 x^{2} - x + 2 k

解答

x = \frac{1 + 1 - 8 ( 2 k - f )}{4}, x = \frac{1 - 1 - 8 ( 2 k - f )}{4}

求解步骤

f = 2 x^{2} - x + 2 k

交换两边

2 x^{2} - x + 2 k = f

将

f

para o lado esquerdo

2 x^{2} - x + 2 k - f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( 2 k - f )}{2 \cdot 2}

化简

(- 1)^{2} - 4 \cdot 2 (2 k - f) : 1 - 8 (2 k - f)

x_{1, 2} = \frac{- ( - 1 ) \pm 1 - 8 ( 2 k - f )}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- ( - 1 ) + 1 - 8 ( 2 k - f )}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 1 - 8 ( 2 k - f )}{2 \cdot 2}

x = \frac{- ( - 1 ) + 1 - 8 ( 2 k - f )}{2 \cdot 2} : \frac{1 + 1 - 8 ( 2 k - f )}{4}

x = \frac{- ( - 1 ) - 1 - 8 ( 2 k - f )}{2 \cdot 2} : \frac{1 - 1 - 8 ( 2 k - f )}{4}

二次方程组的解是:

x = \frac{1 + 1 - 8 ( 2 k - f )}{4}, x = \frac{1 - 1 - 8 ( 2 k - f )}{4}

作图

流行的例子

7 v^{2} = 89 - 14 v

2 x^{2} + 11 x - 30 = 0

-3x^2-42x-120=0

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