2x(x+3)+2(x+3)=0

解

2 x (x + 3) + 2 (x + 3) = 0

x = - 1, x = - 3

解答ステップ

2 x (x + 3) + 2 (x + 3) = 0

拡張

2 x (x + 3) + 2 (x + 3) : 2 x^{2} + 8 x + 6

2 x^{2} + 8 x + 6 = 0

解くとthe二次式

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 8 + 4}{2 \cdot 2}, x_{2} = \frac{- 8 - 4}{2 \cdot 2}

x = \frac{- 8 + 4}{2 \cdot 2} : - 1

x = \frac{- 8 - 4}{2 \cdot 2} : - 3

二次equationの解:

x = - 1, x = - 3