4v^2-12v=0

解

4 v^{2} - 12 v = 0

v = 3, v = 0

解答ステップ

4 v^{2} - 12 v = 0

解くとthe二次式

v_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 0 = 12

v_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 4}

解を分離する

v_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 4}, v_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 4}

v = \frac{- ( - 12 ) + 12}{2 \cdot 4} : 3

v = \frac{- ( - 12 ) - 12}{2 \cdot 4} : 0

二次equationの解:

v = 3, v = 0