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人気のある代数 >

2p^2+8p+(k+1)=0

解

2 p^{2} + 8 p + (k + 1) = 0

解

p = \frac{- 8 + - 8 k + 56}{4}, p = \frac{- 8 - - 8 k + 56}{4}

解答ステップ

2 p^{2} + 8 p + (k + 1) = 0

改良

2 p^{2} + 8 p + k + 1 = 0

解くとthe二次式

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( k + 1 )}{2 \cdot 2}

簡素化

8^{2} - 4 \cdot 2 (k + 1) : - 8 k + 56

p_{1, 2} = \frac{- 8 \pm - 8 k + 56}{2 \cdot 2}

解を分離する

p_{1} = \frac{- 8 + - 8 k + 56}{2 \cdot 2}, p_{2} = \frac{- 8 - - 8 k + 56}{2 \cdot 2}

p = \frac{- 8 + - 8 k + 56}{2 \cdot 2} : \frac{- 8 + - 8 k + 56}{4}

p = \frac{- 8 - - 8 k + 56}{2 \cdot 2} : \frac{- 8 - - 8 k + 56}{4}

二次equationの解:

p = \frac{- 8 + - 8 k + 56}{4}, p = \frac{- 8 - - 8 k + 56}{4}

グラフ

人気の例

quadraticformula x^2+2x-3=0

q u a d r a t i c f or m u l a x^{2} + 2 x - 3 = 0

quadraticformula s^2+2s+2=0

q u a d r a t i c f or m u l a s^{2} + 2 s + 2 = 0

\frac{x}{3} = x^{2}

(2 x - 9) (x + 2) = 24

solvefor x,(x-y^2)(x+xy)=4

so l v e f or x, (x - y^{2}) (x + x y) = 4