What are the solutions to the equation x^2+6x+1=-4 ?

The solutions to the equation x^2+6x+1=-4 are x=-1,x=-5

Find the zeros of x^2+6x+1=-4

The zeros of x^2+6x+1=-4 are x=-1,x=-5

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x^{2} + 6 x + 1 = - 4

x = - 1, x = - 5

Solution steps

x^{2} + 6 x + 1 = - 4

Move

4

to the left side

x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 \cdot 1}, x_{2} = \frac{- 6 - 4}{2 \cdot 1}

x = \frac{- 6 + 4}{2 \cdot 1} : - 1

x = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

x^{2} + 3 x - 18 = 0

x^{2} + 8 x + 5 = 0

5 y^{2} + 16 y + 64

- 9 x^{2} + 40 x + 84 = 0

x^{2} - 12 x + 100 = 80

What are the solutions to the equation x^2+6x+1=-4 ?
The solutions to the equation x^2+6x+1=-4 are x=-1,x=-5
Find the zeros of x^2+6x+1=-4
The zeros of x^2+6x+1=-4 are x=-1,x=-5