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受欢迎的代数 >

3n^2+21n-510=0

解答

3 n^{2} + 21 n - 510 = 0

解答

n = 10, n = - 17

求解步骤

3 n^{2} + 21 n - 510 = 0

使用求根公式求解

n_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 3 ( - 510 )}{2 \cdot 3}

2 1^{2} - 4 \cdot 3 (- 510) = 81

n_{1, 2} = \frac{- 21 \pm 81}{2 \cdot 3}

将解分隔开

n_{1} = \frac{- 21 + 81}{2 \cdot 3}, n_{2} = \frac{- 21 - 81}{2 \cdot 3}

n = \frac{- 21 + 81}{2 \cdot 3} : 10

n = \frac{- 21 - 81}{2 \cdot 3} : - 17

二次方程组的解是:

n = 10, n = - 17

作图

流行的例子

432=(2x+18)(2x+12)

432 = (2 x + 18) (2 x + 12)

2 x^{2} = - 10 x

\frac{2}{3} x^{2} + 14 = 20

6 x - 3 x^{2} = 3

2 x^{2} - x - 14 = 0