a^2-10a+24=0

解

a^{2} - 10 a + 24 = 0

a = 6, a = 4

解答ステップ

a^{2} - 10 a + 24 = 0

解くとthe二次式

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

a_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

解を分離する

a_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

a = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

a = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

二次equationの解:

a = 6, a = 4