What are the solutions to the equation 42x^2-36x+6=0 ?

The solutions to the equation 42x^2-36x+6=0 are x=(3+sqrt(2))/7 ,x=(3-sqrt(2))/7

Find the zeros of 42x^2-36x+6=0

The zeros of 42x^2-36x+6=0 are x=(3+sqrt(2))/7 ,x=(3-sqrt(2))/7

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42 x^{2} - 36 x + 6 = 0

x = \frac{3 + 2}{7}, x = \frac{3 - 2}{7}

Decimal Notation

x = 0.63060 \dots, x = 0.22654 \dots

Solution steps

42 x^{2} - 36 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 42 \cdot 6}{2 \cdot 42}

(- 36)^{2} - 4 \cdot 42 \cdot 6 = 122

x_{1, 2} = \frac{- ( - 36 ) \pm 12 2}{2 \cdot 42}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 12 2}{2 \cdot 42}, x_{2} = \frac{- ( - 36 ) - 12 2}{2 \cdot 42}

x = \frac{- ( - 36 ) + 12 2}{2 \cdot 42} : \frac{3 + 2}{7}

x = \frac{- ( - 36 ) - 12 2}{2 \cdot 42} : \frac{3 - 2}{7}

The solutions to the quadratic equation are:

x = \frac{3 + 2}{7}, x = \frac{3 - 2}{7}

r, r^{2} + t^{2} = r (t)^{2}

x, 4 x^{2} - 25 y^{2} = 0

0.000003 x^{2} - 0.006 x + 6 = 0

x^{2} + 6 x - 25 = 0

4 x^{2} + 12 x + 9 = 48

What are the solutions to the equation 42x^2-36x+6=0 ?
The solutions to the equation 42x^2-36x+6=0 are x=(3+sqrt(2))/7 ,x=(3-sqrt(2))/7
Find the zeros of 42x^2-36x+6=0
The zeros of 42x^2-36x+6=0 are x=(3+sqrt(2))/7 ,x=(3-sqrt(2))/7