3x^2+27x+60=0

解

3 x^{2} + 27 x + 60 = 0

x = - 4, x = - 5

解答ステップ

3 x^{2} + 27 x + 60 = 0

解くとthe二次式

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 3 \cdot 60}{2 \cdot 3}

2 7^{2} - 4 \cdot 3 \cdot 60 = 3

x_{1, 2} = \frac{- 27 \pm 3}{2 \cdot 3}

解を分離する

x_{1} = \frac{- 27 + 3}{2 \cdot 3}, x_{2} = \frac{- 27 - 3}{2 \cdot 3}

x = \frac{- 27 + 3}{2 \cdot 3} : - 4

x = \frac{- 27 - 3}{2 \cdot 3} : - 5

二次equationの解:

x = - 4, x = - 5