n^2+11n-26=0

解

n^{2} + 11 n - 26 = 0

n = 2, n = - 13

解答ステップ

n^{2} + 11 n - 26 = 0

解くとthe二次式

n_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 26) = 15

n_{1, 2} = \frac{- 11 \pm 15}{2 \cdot 1}

解を分離する

n_{1} = \frac{- 11 + 15}{2 \cdot 1}, n_{2} = \frac{- 11 - 15}{2 \cdot 1}

n = \frac{- 11 + 15}{2 \cdot 1} : 2

n = \frac{- 11 - 15}{2 \cdot 1} : - 13

二次equationの解:

n = 2, n = - 13