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受欢迎的代数 >

4x^2+(m+2)x+6=0

解答

4 x^{2} + (m + 2) x + 6 = 0

解答

x = \frac{- m - 2 + m ^{2} + 4 m - 92}{8}, x = \frac{- m - 2 - m ^{2} + 4 m - 92}{8}

求解步骤

4 x^{2} + (m + 2) x + 6 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( m + 2 ) \pm ( m + 2 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

化简

(m + 2)^{2} - 4 \cdot 4 \cdot 6 : m^{2} + 4 m - 92

x_{1, 2} = \frac{- ( m + 2 ) \pm m ^{2} + 4 m - 92}{2 \cdot 4}

将解分隔开

x_{1} = \frac{- ( m + 2 ) + m ^{2} + 4 m - 92}{2 \cdot 4}, x_{2} = \frac{- ( m + 2 ) - m ^{2} + 4 m - 92}{2 \cdot 4}

x = \frac{- ( m + 2 ) + m ^{2} + 4 m - 92}{2 \cdot 4} : \frac{- m - 2 + m ^{2} + 4 m - 92}{8}

x = \frac{- ( m + 2 ) - m ^{2} + 4 m - 92}{2 \cdot 4} : \frac{- m - 2 - m ^{2} + 4 m - 92}{8}

二次方程组的解是:

x = \frac{- m - 2 + m ^{2} + 4 m - 92}{8}, x = \frac{- m - 2 - m ^{2} + 4 m - 92}{8}

作图

流行的例子

- t^{2} + 10 t = 16

2 x^{2} - 11 x + 3 = 0

(18-y)^2+y^2=180

(18 - y)^{2} + y^{2} = 180

5 x^{2} - 9 = 0

solvefor y,(16-x)y^2=x^3

so l v e f or y, (16 - x) y^{2} = x^{3}