quadraticformula x^2+4x-5=0

解

x^{2} + 4 x - 5 = 0

x = 1, x = - 5

解答ステップ

x^{2} + 4 x - 5 = 0

解くとthe二次式

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

二次equationの解:

x = 1, x = - 5