What are the solutions to the equation 2x^2-12x+23=0 ?

The solutions to the equation 2x^2-12x+23=0 are x=3+isqrt(5/2),x=3-isqrt(5/2)

Find the zeros of 2x^2-12x+23=0

The zeros of 2x^2-12x+23=0 are x=3+isqrt(5/2),x=3-isqrt(5/2)

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2 x^{2} - 12 x + 23 = 0

x = 3 + i \frac{5}{2}, x = 3 - i \frac{5}{2}

Solution steps

2 x^{2} - 12 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 23}{2 \cdot 2}

Simplify

(- 12)^{2} - 4 \cdot 2 \cdot 23 : 210 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 10 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 10 i}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 2 10 i}{2 \cdot 2}

x = \frac{- ( - 12 ) + 2 10 i}{2 \cdot 2} : 3 + i \frac{5}{2}

x = \frac{- ( - 12 ) - 2 10 i}{2 \cdot 2} : 3 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = 3 + i \frac{5}{2}, x = 3 - i \frac{5}{2}

x^{2} + 16 x + 8 = 0

(x - 10)^{2} + 10 = 100

4 x^{2} - 6 x = 6 x

- 5 x^{2} + x - 4 = 0

m^{2} + 49 = 0

What are the solutions to the equation 2x^2-12x+23=0 ?
The solutions to the equation 2x^2-12x+23=0 are x=3+isqrt(5/2),x=3-isqrt(5/2)
Find the zeros of 2x^2-12x+23=0
The zeros of 2x^2-12x+23=0 are x=3+isqrt(5/2),x=3-isqrt(5/2)