zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor y,f=x^3y^2-2x^2y+3x

解答

求解

y, f = x^{3} y^{2} - 2 x^{2} y + 3 x

解答

y = \frac{x + x ( 2 x + f )}{x ^{2}}, y = \frac{x - x ( 2 x + f )}{x ^{2}}; x \neq = 0

求解步骤

f = x^{3} y^{2} - 2 x^{2} y + 3 x

交换两边

x^{3} y^{2} - 2 x^{2} y + 3 x = f

将

f

para o lado esquerdo

x^{3} y^{2} - 2 x^{2} y + 3 x - f = 0

使用求根公式求解

y_{1, 2} = \frac{- ( - 2 x ^{2} ) \pm ( - 2 x ^{2} ) ^{2} - 4 x ^{3} ( 3 x - f )}{2 x ^{3}}

化简

(- 2 x^{2})^{2} - 4 x^{3} (3 x - f) : 2 x x (2 x + f)

y_{1, 2} = \frac{- ( - 2 x ^{2} ) \pm 2 x x ( 2 x + f )}{2 x ^{3}}; x \neq = 0

将解分隔开

y_{1} = \frac{- ( - 2 x ^{2} ) + 2 x x ( 2 x + f )}{2 x ^{3}}, y_{2} = \frac{- ( - 2 x ^{2} ) - 2 x x ( 2 x + f )}{2 x ^{3}}

y = \frac{- ( - 2 x ^{2} ) + 2 x x ( 2 x + f )}{2 x ^{3}} : \frac{x + x ( 2 x + f )}{x ^{2}}

y = \frac{- ( - 2 x ^{2} ) - 2 x x ( 2 x + f )}{2 x ^{3}} : \frac{x - x ( 2 x + f )}{x ^{2}}

二次方程组的解是:

y = \frac{x + x ( 2 x + f )}{x ^{2}}, y = \frac{x - x ( 2 x + f )}{x ^{2}}; x \neq = 0

作图

流行的例子

4 a^{2} - 13 a + 3 = 0

- 13 - 5 x = - 5 x^{2}

y^{2} + 13 y + 42 = 0

solvefor x,7x^2+3x-2=0

so l v e f or x, 7 x^{2} + 3 x - 2 = 0

(2(3/2)-1)x^2+4x+2=0

(2 (\frac{3}{2}) - 1) x^{2} + 4 x + 2 = 0