What are the solutions to the equation w^2+6w-7=0 ?

The solutions to the equation w^2+6w-7=0 are w=1,w=-7

Find the zeros of w^2+6w-7=0

The zeros of w^2+6w-7=0 are w=1,w=-7

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w^{2} + 6 w - 7 = 0

w = 1, w = - 7

Solution steps

w^{2} + 6 w - 7 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

w_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 6 + 8}{2 \cdot 1}, w_{2} = \frac{- 6 - 8}{2 \cdot 1}

w = \frac{- 6 + 8}{2 \cdot 1} : 1

w = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

w = 1, w = - 7

s^{2} + 8 s + 20

12 x^{2} - 4 x - 40 = 0

2 x^{2} + B x + 3 = 0

5 x^{2} + 7 + 3 x = - 3 x

15 a^{2} + 4 a - 3 = 0

What are the solutions to the equation w^2+6w-7=0 ?
The solutions to the equation w^2+6w-7=0 are w=1,w=-7
Find the zeros of w^2+6w-7=0
The zeros of w^2+6w-7=0 are w=1,w=-7