What are the solutions to the equation 6x^2-12x-7=0 ?

The solutions to the equation 6x^2-12x-7=0 are x=(6+sqrt(78))/6 ,x=(6-sqrt(78))/6

Find the zeros of 6x^2-12x-7=0

The zeros of 6x^2-12x-7=0 are x=(6+sqrt(78))/6 ,x=(6-sqrt(78))/6

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6 x^{2} - 12 x - 7 = 0

x = \frac{6 + 78}{6}, x = \frac{6 - 78}{6}

Decimal Notation

x = 2.47196 \dots, x = - 0.47196 \dots

Solution steps

6 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 (- 7) = 278

x_{1, 2} = \frac{- ( - 12 ) \pm 2 78}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 78}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 2 78}{2 \cdot 6}

x = \frac{- ( - 12 ) + 2 78}{2 \cdot 6} : \frac{6 + 78}{6}

x = \frac{- ( - 12 ) - 2 78}{2 \cdot 6} : \frac{6 - 78}{6}

The solutions to the quadratic equation are:

x = \frac{6 + 78}{6}, x = \frac{6 - 78}{6}

2 x^{2} - 8 x = - 6

- 16 t^{2} + 55 t + 10 = 0

x, x^{2} + y^{2} = C

x, x^{2} - 2 y^{3} + 4 y = 2

20 x^{2} + 11 x - 3 = 0

What are the solutions to the equation 6x^2-12x-7=0 ?
The solutions to the equation 6x^2-12x-7=0 are x=(6+sqrt(78))/6 ,x=(6-sqrt(78))/6
Find the zeros of 6x^2-12x-7=0
The zeros of 6x^2-12x-7=0 are x=(6+sqrt(78))/6 ,x=(6-sqrt(78))/6