2m^2+10m-28=0

解

2 m^{2} + 10 m - 28 = 0

m = 2, m = - 7

解答ステップ

2 m^{2} + 10 m - 28 = 0

解くとthe二次式

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 28 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 28) = 18

m_{1, 2} = \frac{- 10 \pm 18}{2 \cdot 2}

解を分離する

m_{1} = \frac{- 10 + 18}{2 \cdot 2}, m_{2} = \frac{- 10 - 18}{2 \cdot 2}

m = \frac{- 10 + 18}{2 \cdot 2} : 2

m = \frac{- 10 - 18}{2 \cdot 2} : - 7

二次equationの解:

m = 2, m = - 7