zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

59=q^2-12q+41

解答

59 = q^{2} - 12 q + 41

解答

q = 3 (2 + 6), q = 3 (2 - 6)

+1

十进制

q = 13.34846 \dots, q = - 1.34846 \dots

求解步骤

59 = q^{2} - 12 q + 41

交换两边

q^{2} - 12 q + 41 = 59

将

59

para o lado esquerdo

q^{2} - 12 q - 18 = 0

使用求根公式求解

q_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 18) = 66

q_{1, 2} = \frac{- ( - 12 ) \pm 6 6}{2 \cdot 1}

将解分隔开

q_{1} = \frac{- ( - 12 ) + 6 6}{2 \cdot 1}, q_{2} = \frac{- ( - 12 ) - 6 6}{2 \cdot 1}

q = \frac{- ( - 12 ) + 6 6}{2 \cdot 1} : 3 (2 + 6)

q = \frac{- ( - 12 ) - 6 6}{2 \cdot 1} : 3 (2 - 6)

二次方程组的解是:

q = 3 (2 + 6), q = 3 (2 - 6)

作图

流行的例子

3x^2-130x+1000=0

3 x^{2} - 130 x + 1000 = 0

2 n^{2} + 5 n + 2 = 0

x (x + 10) + 20 = - 5

10 x^{2} - 60 x = 0

solvefor x,9x^2-4y^2=0

so l v e f or x, 9 x^{2} - 4 y^{2} = 0