What are the solutions to the equation 4n^2-8n-12=0 ?

The solutions to the equation 4n^2-8n-12=0 are n=3,n=-1

Find the zeros of 4n^2-8n-12=0

The zeros of 4n^2-8n-12=0 are n=3,n=-1

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4 n^{2} - 8 n - 12 = 0

n = 3, n = - 1

Solution steps

4 n^{2} - 8 n - 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 12) = 16

n_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 4}, n_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 4}

n = \frac{- ( - 8 ) + 16}{2 \cdot 4} : 3

n = \frac{- ( - 8 ) - 16}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

n = 3, n = - 1

x, 4 x^{2} - 16 x = 0

3 x^{2} - 9 x - 6 = 0

11 x^{2} + 18 x - 7 = 0

- x^{2} - 3 x + 7 = 0

x, - x^{2} + 3 x + 40 = 0

What are the solutions to the equation 4n^2-8n-12=0 ?
The solutions to the equation 4n^2-8n-12=0 are n=3,n=-1
Find the zeros of 4n^2-8n-12=0
The zeros of 4n^2-8n-12=0 are n=3,n=-1