3y^2-9y=0

解

3 y^{2} - 9 y = 0

y = 3, y = 0

解答ステップ

3 y^{2} - 9 y = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 \cdot 0 = 9

y_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 3}

解を分離する

y_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 3}, y_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 3}

y = \frac{- ( - 9 ) + 9}{2 \cdot 3} : 3

y = \frac{- ( - 9 ) - 9}{2 \cdot 3} : 0

二次equationの解:

y = 3, y = 0