What are the solutions to the equation x^2+4x+(-1)=0 ?

The solutions to the equation x^2+4x+(-1)=0 are x=-2+sqrt(5),x=-2-sqrt(5)

Find the zeros of x^2+4x+(-1)=0

The zeros of x^2+4x+(-1)=0 are x=-2+sqrt(5),x=-2-sqrt(5)

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x^{2} + 4 x + (- 1) = 0

x = - 2 + 5, x = - 2 - 5

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

x^{2} + 4 x + (- 1) = 0

Refine

x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 1) = 25

x_{1, 2} = \frac{- 4 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 5}{2 \cdot 1}

x = \frac{- 4 + 2 5}{2 \cdot 1} : - 2 + 5

x = \frac{- 4 - 2 5}{2 \cdot 1} : - 2 - 5

The solutions to the quadratic equation are:

x = - 2 + 5, x = - 2 - 5

x, f = x^{2} + y^{2} + x (y - z) - 4 x - 6 y + 4 z + 30

m^{2} - 4 m - 32 = 0

A, (A + X)^{2} = BC

x^{2} - x = 0

2 x^{2} + 3 x - 5 = 0

What are the solutions to the equation x^2+4x+(-1)=0 ?
The solutions to the equation x^2+4x+(-1)=0 are x=-2+sqrt(5),x=-2-sqrt(5)
Find the zeros of x^2+4x+(-1)=0
The zeros of x^2+4x+(-1)=0 are x=-2+sqrt(5),x=-2-sqrt(5)