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人気のある代数 >

(m+3)x^2+2m=(2m-5)x+10

解

(m + 3) x^{2} + 2 m = (2 m - 5) x + 10

解

x = \frac{2 m - 5 + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}, x = \frac{2 m - 5 - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}; m \neq = - 3

解答ステップ

(m + 3) x^{2} + 2 m = (2 m - 5) x + 10

10

を左側に移動します

(m + 3) x^{2} + 2 m - 10 = (2 m - 5) x

(2 m - 5) x

を左側に移動します

(m + 3) x^{2} + 2 m - 10 - (2 m - 5) x = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(m + 3) x^{2} + (- 2 m + 5) x + 2 m - 10 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 2 m + 5 ) \pm ( - 2 m + 5 ) ^{2} - 4 ( m + 3 ) ( 2 m - 10 )}{2 ( m + 3 )}

簡素化

(- 2 m + 5)^{2} - 4 (m + 3) (2 m - 10) : - 4 m^{2} - 4 m + 145

x_{1, 2} = \frac{- ( - 2 m + 5 ) \pm - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}; m \neq = - 3

解を分離する

x_{1} = \frac{- ( - 2 m + 5 ) + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}, x_{2} = \frac{- ( - 2 m + 5 ) - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}

x = \frac{- ( - 2 m + 5 ) + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )} : \frac{2 m - 5 + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}

x = \frac{- ( - 2 m + 5 ) - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )} : \frac{2 m - 5 - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}

二次equationの解:

x = \frac{2 m - 5 + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}, x = \frac{2 m - 5 - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}; m \neq = - 3

グラフ

人気の例

- 2 x^{2} + 8 x + 12 = 0

solvefor X,X^2+Y^2+16=0

so l v e f or X, X^{2} + Y^{2} + 16 = 0

5 x^{2} - 54 x + 94 = - 5

p^{2} - 8 p + 15 = 0

2 x^{2} + 10 x + 9 = 0