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受欢迎的代数 >

(m+3)x^2+2m=(2m-5)x+10

解答

(m + 3) x^{2} + 2 m = (2 m - 5) x + 10

解答

x = \frac{2 m - 5 + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}, x = \frac{2 m - 5 - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}; m \neq = - 3

求解步骤

(m + 3) x^{2} + 2 m = (2 m - 5) x + 10

将

10

para o lado esquerdo

(m + 3) x^{2} + 2 m - 10 = (2 m - 5) x

将

(2 m - 5) x

para o lado esquerdo

(m + 3) x^{2} + 2 m - 10 - (2 m - 5) x = 0

改写成标准形式

a x^{2} + b x + c = 0

(m + 3) x^{2} + (- 2 m + 5) x + 2 m - 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 m + 5 ) \pm ( - 2 m + 5 ) ^{2} - 4 ( m + 3 ) ( 2 m - 10 )}{2 ( m + 3 )}

化简

(- 2 m + 5)^{2} - 4 (m + 3) (2 m - 10) : - 4 m^{2} - 4 m + 145

x_{1, 2} = \frac{- ( - 2 m + 5 ) \pm - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}; m \neq = - 3

将解分隔开

x_{1} = \frac{- ( - 2 m + 5 ) + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}, x_{2} = \frac{- ( - 2 m + 5 ) - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}

x = \frac{- ( - 2 m + 5 ) + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )} : \frac{2 m - 5 + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}

x = \frac{- ( - 2 m + 5 ) - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )} : \frac{2 m - 5 - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}

二次方程组的解是:

x = \frac{2 m - 5 + - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}, x = \frac{2 m - 5 - - 4 m ^{2} - 4 m + 145}{2 ( m + 3 )}; m \neq = - 3

作图

流行的例子

- 2 x^{2} + 8 x + 12 = 0

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so l v e f or X, X^{2} + Y^{2} + 16 = 0

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