What are the solutions to the equation x^2+16=-28 ?

The solutions to the equation x^2+16=-28 are x=2sqrt(11)i,x=-2sqrt(11)i

Find the zeros of x^2+16=-28

The zeros of x^2+16=-28 are x=2sqrt(11)i,x=-2sqrt(11)i

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x^{2} + 16 = - 28

x = 211 i, x = - 211 i

Solution steps

x^{2} + 16 = - 28

Move

16

to the right side

x^{2} = - 44

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 44, x = - - 44

- 44 = 211 i

- - 44 = - 211 i

x = 211 i, x = - 211 i

8 = 4 + 17 t - 16 t^{2}

c^{2} - 5 c + 1 = 0

6 + 6 r^{2} = 15 r

x (2 x - 5) = 3 (x - 2)

6 q^{2} - 84 q + 228 = 0

What are the solutions to the equation x^2+16=-28 ?
The solutions to the equation x^2+16=-28 are x=2sqrt(11)i,x=-2sqrt(11)i
Find the zeros of x^2+16=-28
The zeros of x^2+16=-28 are x=2sqrt(11)i,x=-2sqrt(11)i