solvefor x,x^2+2y^2+3z^2=1

解

解く

x, x^{2} + 2 y^{2} + 3 z^{2} = 1

x = 1 - 2 y^{2} - 3 z^{2}, x = - 1 - 2 y^{2} - 3 z^{2}

解答ステップ

x^{2} + 2 y^{2} + 3 z^{2} = 1

2 y^{2}

を右側に移動します

x^{2} + 3 z^{2} = 1 - 2 y^{2}

3 z^{2}

を右側に移動します

x^{2} = 1 - 2 y^{2} - 3 z^{2}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = 1 - 2 y^{2} - 3 z^{2}, x = - 1 - 2 y^{2} - 3 z^{2}