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受欢迎的代数 >

2x^2+2x+7=0

解答

2 x^{2} + 2 x + 7 = 0

解答

x = - \frac{1}{2} + i \frac{13}{2}, x = - \frac{1}{2} - i \frac{13}{2}

求解步骤

2 x^{2} + 2 x + 7 = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

化简

2^{2} - 4 \cdot 2 \cdot 7 : 213 i

x_{1, 2} = \frac{- 2 \pm 2 13 i}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- 2 + 2 13 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 13 i}{2 \cdot 2}

x = \frac{- 2 + 2 13 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{13}{2}

x = \frac{- 2 - 2 13 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{13}{2}

二次方程组的解是:

x = - \frac{1}{2} + i \frac{13}{2}, x = - \frac{1}{2} - i \frac{13}{2}

作图

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