k^2-7k+6=0

解

k^{2} - 7 k + 6 = 0

k = 6, k = 1

解答ステップ

k^{2} - 7 k + 6 = 0

解くとthe二次式

k_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

k_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

解を分離する

k_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, k_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

k = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

k = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

二次equationの解:

k = 6, k = 1