g^2-10g+16=0

解

g^{2} - 10 g + 16 = 0

g = 8, g = 2

解答ステップ

g^{2} - 10 g + 16 = 0

解くとthe二次式

g_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

g_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

解を分離する

g_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, g_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

g = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

g = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

二次equationの解:

g = 8, g = 2