What are the solutions to the equation 3x^2+10+15x+20=180 ?

The solutions to the equation 3x^2+10+15x+20=180 are x=5,x=-10

Find the zeros of 3x^2+10+15x+20=180

The zeros of 3x^2+10+15x+20=180 are x=5,x=-10

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3 x^{2} + 10 + 15 x + 20 = 180

x = 5, x = - 10

Solution steps

3 x^{2} + 10 + 15 x + 20 = 180

Refine

3 x^{2} + 15 x + 30 = 180

Move

180

to the left side

3 x^{2} + 15 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 ( - 150 )}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 (- 150) = 45

x_{1, 2} = \frac{- 15 \pm 45}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 45}{2 \cdot 3}, x_{2} = \frac{- 15 - 45}{2 \cdot 3}

x = \frac{- 15 + 45}{2 \cdot 3} : 5

x = \frac{- 15 - 45}{2 \cdot 3} : - 10

The solutions to the quadratic equation are:

x = 5, x = - 10

3 x^{2} - 5 x - 13 = 0

x, z = x^{2} - 4 x y - 2 y^{2} + 12 x - 12 y - 1

6 x^{2} - 108 = 0

w^{2} - 84 = 0

3 x (x - 1) = 0

What are the solutions to the equation 3x^2+10+15x+20=180 ?
The solutions to the equation 3x^2+10+15x+20=180 are x=5,x=-10
Find the zeros of 3x^2+10+15x+20=180
The zeros of 3x^2+10+15x+20=180 are x=5,x=-10