n^2+7n+12=0

解

n^{2} + 7 n + 12 = 0

n = - 3, n = - 4

解答ステップ

n^{2} + 7 n + 12 = 0

解くとthe二次式

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

n_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

解を分離する

n_{1} = \frac{- 7 + 1}{2 \cdot 1}, n_{2} = \frac{- 7 - 1}{2 \cdot 1}

n = \frac{- 7 + 1}{2 \cdot 1} : - 3

n = \frac{- 7 - 1}{2 \cdot 1} : - 4

二次equationの解:

n = - 3, n = - 4