What are the solutions to the equation 20x^2+25x=0 ?

The solutions to the equation 20x^2+25x=0 are x=0,x=-5/4

Find the zeros of 20x^2+25x=0

The zeros of 20x^2+25x=0 are x=0,x=-5/4

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20 x^{2} + 25 x = 0

x = 0, x = - \frac{5}{4}

Decimal Notation

x = 0, x = - 1.25

Solution steps

20 x^{2} + 25 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 20 \cdot 0}{2 \cdot 20}

2 5^{2} - 4 \cdot 20 \cdot 0 = 25

x_{1, 2} = \frac{- 25 \pm 25}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 25 + 25}{2 \cdot 20}, x_{2} = \frac{- 25 - 25}{2 \cdot 20}

x = \frac{- 25 + 25}{2 \cdot 20} : 0

x = \frac{- 25 - 25}{2 \cdot 20} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{4}

4 m^{2} - 64 = 0

2 x^{2} + 12 x - 15

(x + 6)^{2} = 12

2 h^{2} - 5 h - 12 = 0

t, f = (t - 6) u_{5} (t) - (t - 5) u_{6} (t)

What are the solutions to the equation 20x^2+25x=0 ?
The solutions to the equation 20x^2+25x=0 are x=0,x=-5/4
Find the zeros of 20x^2+25x=0
The zeros of 20x^2+25x=0 are x=0,x=-5/4