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(1.489-2.48I)^2+(1.49-2.48I)^2=0

解答

(1.489 - 2.48 I)^{2} + (1.49 - 2.48 I)^{2} = 0

解答

I = \frac{14.77584}{24.6016} + i \frac{0.0000246016}{24.6016}, I = \frac{14.77584}{24.6016} - i \frac{0.0000246016}{24.6016}

求解步骤

(1.489 - 2.48 I)^{2} + (1.49 - 2.48 I)^{2} = 0

展开

(1.489 - 2.48 I)^{2} + (1.49 - 2.48 I)^{2} : 12.3008 I^{2} - 14.77584 I + 4.437221

12.3008 I^{2} - 14.77584 I + 4.437221 = 0

使用求根公式求解

I_{1, 2} = \frac{- ( - 14.77584 ) \pm ( - 14.77584 ) ^{2} - 4 \cdot 12.3008 \cdot 4.437221}{2 \cdot 12.3008}

化简

(- 14.77584)^{2} - 4 \cdot 12.3008 \cdot 4.437221 : 0.0000246016 i

I_{1, 2} = \frac{- ( - 14.77584 ) \pm 0.0000246016 i}{2 \cdot 12.3008}

将解分隔开

I_{1} = \frac{- ( - 14.77584 ) + 0.0000246016 i}{2 \cdot 12.3008}, I_{2} = \frac{- ( - 14.77584 ) - 0.0000246016 i}{2 \cdot 12.3008}

I = \frac{- ( - 14.77584 ) + 0.0000246016 i}{2 \cdot 12.3008} : \frac{14.77584}{24.6016} + i \frac{0.0000246016}{24.6016}

I = \frac{- ( - 14.77584 ) - 0.0000246016 i}{2 \cdot 12.3008} : \frac{14.77584}{24.6016} - i \frac{0.0000246016}{24.6016}

二次方程组的解是:

I = \frac{14.77584}{24.6016} + i \frac{0.0000246016}{24.6016}, I = \frac{14.77584}{24.6016} - i \frac{0.0000246016}{24.6016}

作图

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