((sqrt(5))/4)^2+y^2=1

Lösung

(\frac{5}{4})^{2} + y^{2} = 1

y = \frac{11}{4}, y = - \frac{11}{4}

Dezimale

y = 0.82915 \dots, y = - 0.82915 \dots

Schritte zur Lösung

(\frac{5}{4})^{2} + y^{2} = 1

Schreibe

(\frac{5}{4})^{2} + y^{2}

um:

\frac{5}{16} + y^{2}

\frac{5}{16} + y^{2} = 1

Verschiebe

\frac{5}{16}

auf die rechte Seite

y^{2} = 1 - \frac{5}{16}

Vereinfache

1 - \frac{5}{16} : \frac{11}{16}

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

y = \frac{11}{16}, y = - \frac{11}{16}

\frac{11}{16} = \frac{11}{4}

- \frac{11}{16} = - \frac{11}{4}

y = \frac{11}{4}, y = - \frac{11}{4}

3 (x - 3) - 3 (x + 3) = (x + 3) (x - 3)

so l v e f or y, x^{2} y^{2} - 4 x^{2} - 4 y^{2} = 0

- 4 x^{2} - 4 x + 5 = 0

co m pl e t es q u a re x^{2} + 7 x + 18

(x - 1)^{2} = 5^{4}